Limit ______________________?

Find the limit as x tends to negative infinity of (2-x)/(sqrt(7 + 6x^2))





Show all steps.|||Hi,


Dividing both numerator and denominator by x, we get the limit as





lim


(1/x)-%26gt;0 (2/x - 1)/(sqrt(7/x^2 + 6))





Putting the limit,





= (0 - 1)/(sqrt(0 + 6))


= -1/sqrt(6)





Hope this helped. :)|||so you have to show what happens as X gets more and more negative ... as X gets more and more negative minus x gets bigger and bigger.... and x squared gets bigger even faster but the sqrt slows things down.. so just plus in some values and see what happens, draw a graph and get a feel for what is going on ... eventually ony -x on the top and the sqrt of X squared (ie X counts) so that looks like it is heading for a limit of 1|||lim


x -%26gt; -inf (2 -x) / sqrt(7+ 6x^2)








lim





x -%26gt; inf (2/x -1) /( sqrt (7/x^2 + 6) { dividing by x throughout)








-1/sqrt(6) 2/x -%26gt;0 and 7/x^2 -%26gt; 0 as x -%26gt; inf