limx---%26gt;o (1-cosx)/sin^2x according to me the answer is 0 but in book the ans is 1/2. which one is right. thnx in advance .|||sin^2 = 1-cos^2 = (1+cos)(1-cos)
lim x-%26gt;0 (1-cos) / (1+cos)(1-cos) = 1 / (1+cos) = 1/2
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