How to evaluate a limit as x approaches infinity with a radical in numerator?

How can I evaluate the limit as x approaches infinity when radical 4x^2+3 is divided by (5x-1)? Asides multiplying by the conjugate, what is the next step? Please help!!|||2/5|||For "large enough" x, the numerator looks like sqrt(4x^2)=2x (i.e., dropping the +3), and the denominator looks like 5x. So the limit will be equivalent to that of (2x)/(5x) = 2/5.





When you have a problem like this, it is best to focus on the largest power of x in the numerator and denominator. sqrt(x^2) is equivalent to x^1.





Oh, and if the limit goes to negative infinity, the the answer is -2/5, since the sign of x will only matter in the denominator; that is, sqrt(x^2) = abs(x).|||what would be your ' conjugate ? '...factor out an x { x = 鈭歺虏 } from top and bottom , take the limit..





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